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chemistry study matter mole problems answer key olution: Molar mass of CaCO₃ = 40.08 + 12.01 + (3 × 16.00) = 100.09 g/mol Moles = 36 g / 100.09 g/mol ≈ 0.36 mol Problem 2: How many grams of sodium chloride (NaCl) are needed to obtain 0.5 moles? Solutio Sep 22, 2025 Read more →
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